Explanation: #M_ (CO_2) = "220 mg"# #MW_ (CO_2) = "44.01 g/mol"# #"O"_2 " molecules = ?"#

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So number of atoms in 0.5 mole of CH_4 is equal to number of molecules in 0.5 mol multiplied by 5. "number of atoms in 0.5 mole of CH_4"= "5⋅number of molecules in 0.5 mol" = …

Sep 5, 2016 · The log is the exponent of the hydrogen ion concentration so the log is -1 but pH is the negative log so # -1 xx -1 # = 1 Example if the solutions is only 1% ( 1/100) or .01 # {H^+}# The the …

Jan 16, 2017 · So #x=0.02mol# (Assuming the acid has been completely nutralized by 1g #CaCO_3#) Hence the strength of the #HCl# solution is #c= (0.02mol)/ (2L)=0.01M# So pH if the solution is #= …

The molality of the "CaCl"_2 is 1.14 mol/kg. > "Molar mass of CaCl"_2·"2H"_2"O" = "110.98 g + 36.03 g" = "147.01 g" "Mass of CaCl"_2 = 7.02 color (red) (cancel ...

The solutions are S= {160.6^@,305.7^@}. The max. and min. are =5 and -5 rcos (theta+alpha)=r (costhetacosalpha+sinthetasinalpha) =rcosthetacosalpha+rsinthetasinalpha) Comparing this to the …

Oct 16, 2017 · We know the following #epsilon-delta# Definition of Limit : #AA epsilon > 0, EE" a "delta > 0," such that, "#

"CO"_2 The question essentially wants you to figure out the molar mass, i.e. the mass of exactly 1 mole, of this compound. Now, the important thing to keep in mind here is that 1 mole of a molecular …

Oct 11, 2015 · 1545 subjects were given ginko & 1524 placebo. In ginko group, 246 developed dementian & in the placebo it was 277 with dementia. Significance level=0.01 to test claim (ginko is …